p^2+14p+15=0

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Solution for p^2+14p+15=0 equation:


Simplifying
p2 + 14p + 15 = 0

Reorder the terms:
15 + 14p + p2 = 0

Solving
15 + 14p + p2 = 0

Solving for variable 'p'.

Begin completing the square.

Move the constant term to the right:

Add '-15' to each side of the equation.
15 + 14p + -15 + p2 = 0 + -15

Reorder the terms:
15 + -15 + 14p + p2 = 0 + -15

Combine like terms: 15 + -15 = 0
0 + 14p + p2 = 0 + -15
14p + p2 = 0 + -15

Combine like terms: 0 + -15 = -15
14p + p2 = -15

The p term is 14p.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14p + 49 + p2 = -15 + 49

Reorder the terms:
49 + 14p + p2 = -15 + 49

Combine like terms: -15 + 49 = 34
49 + 14p + p2 = 34

Factor a perfect square on the left side:
(p + 7)(p + 7) = 34

Calculate the square root of the right side: 5.830951895

Break this problem into two subproblems by setting 
(p + 7) equal to 5.830951895 and -5.830951895.

Subproblem 1

p + 7 = 5.830951895 Simplifying p + 7 = 5.830951895 Reorder the terms: 7 + p = 5.830951895 Solving 7 + p = 5.830951895 Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + p = 5.830951895 + -7 Combine like terms: 7 + -7 = 0 0 + p = 5.830951895 + -7 p = 5.830951895 + -7 Combine like terms: 5.830951895 + -7 = -1.169048105 p = -1.169048105 Simplifying p = -1.169048105

Subproblem 2

p + 7 = -5.830951895 Simplifying p + 7 = -5.830951895 Reorder the terms: 7 + p = -5.830951895 Solving 7 + p = -5.830951895 Solving for variable 'p'. Move all terms containing p to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + p = -5.830951895 + -7 Combine like terms: 7 + -7 = 0 0 + p = -5.830951895 + -7 p = -5.830951895 + -7 Combine like terms: -5.830951895 + -7 = -12.830951895 p = -12.830951895 Simplifying p = -12.830951895

Solution

The solution to the problem is based on the solutions from the subproblems. p = {-1.169048105, -12.830951895}

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